计算或化简:[(x-y)/(x+3y)]÷[(x²-y²)/(x²+6xy+9y²)]-(2y)/x+y

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计算或化简:[(x-y)/(x+3y)]÷[(x²-y²)/(x²+6xy+9y²)]-(2y)/x+y

原式=[(x-y)/(x+3y)]×[(x+3y)²/(x+y)(x-y)]-2y/(x+y)
=(x+3y)/(x+y)-2y/(x+y)
=(x+3y-2y)/(x+y)
=(x+y)/(x+y)
=1

[(x-y)/(x+3y)]÷[(x²-y²)/(x²+6xy+9y²)]-(2y)/x+y
=[(x-y)/(x+3y)]÷[(x+y)(x-y)/(x+3y)²]-(2y)/x+y
=[(x-y)/(x+3y)]*(x+3y)²/(x+y)(x-y)-(2y)/x+y
=(x+3y)/(x+y)-(2y)/x+y
=(x+y)/(x+y)
=1

原式=(x-y)/(x+3y)*[(x²+6xy+9y²)/(x²-y²)]-2y/(x+y)
=(x-y)/(x+3y)*[(x+3y)²/(x+y)(x-y)]-2y/(x+y)
=(x+3y)/(x+y)-2y/(x+y)
=1