[sin(A-派)cot(A-2派)]/[cos(A-派)tan(A-2派)]

来源:学生作业学帮网 编辑:学帮网 时间:2024/04/28 17:11:09

[sin(A-派)cot(A-2派)]/[cos(A-派)tan(A-2派)]

sin(A-派)=-sin A
cos(A-派)=-cos A
cot A=cos A/sin A
tan A=sin A/cos A
所以[sin(A-派)cot(A-2派)]/[cos(A-派)tan(A-2派)]
=-sin Acot A/(-cos Atan A)
=-cos A/(-sin A)
=cot A