arctan求导
arctan(1/x)求导[arctan(1/x)]'=1/[1+(1/x)^2]*(1/x)'=[x^2/(1+x^2)]*(-1/x^2)=-1/(1+x^2)[arctan(1/x)]'={1/[(1/x)^2+1]}(1/x)'=(
求导:y=arctan(lnx)y=arctan(lnx)y'=1/(1+ln^2x)*1/x=1/[x(1+ln^2x)]y=arctan(lnx)tany=tan(lnx)(secy)^2dy/dx=(1/x)[sec(lnx)]^2d
y=arctan(lnx)求导~对于这样的复合函数,求导就用链式法则,对各个函数逐个求导,在这里y=arctan(lnx),可以令lnx=t,那么y'=(arctant)'*t',显然(arctant)'=1/(1+t²),而t'
y=arctan(1/x)求导y'=1/[1+(1/x)^2]*(1/x)'=x^2/(1+x^2)*(-1/x^2)=-1/(1+x^2)
y=arctan(x/2)求导? 1/2*1/(1+(x/2)^2)
arctan根号(x^2-1)求导,u=x²-1,则u'=2xv=√u,则v'=1/(2√u)*u'=2x/(2√u)=x/√(x²-1)所以令y=arctan√(x²-1)=arctanv则y'=1/(1+v
y=arctan√x求导解y=arctan√xy'=(arctan√x)'=1/(1+x)(√x)'=1/2√x(1+x)
求导y=(arctanx)^2y=(arctanx)^2y'=2arctanx*(arctanx)'=2arctanx/(1+x²)y=2arctanx除以(1+x^2)
求导y=arctan[2x/(1-x^2)]
急等求导Y=ARCTANx/1+x^2y=arctanx/(1+x²)那么y'=1/[1+x²/(1+x²)²]*[x/(1+x²)]'=(1+x²)²/[(1+x
函数求导.y=arctan(x+1)/(x-1)y=arctan(x+1)/(x-1)y'=1/[1+(x+1)^2/(x-1)^2]*[(x+1)/(x-1)]'=1/[1+(x+1)^2/(x-1)^2]*[(x-1)-(x+1)]/(
隐函数求导x=y+arctany两边对x求导:1=y'+y'/(1+y^2)解得:y'=1/[1+1/(1+y^2)]=(1+y^2)/(2+y^2)
求导y=arctan(根号(1-3x))如题、因为,(tanx)’=1/cos²x,Y^(-1){Y的反函数}=tanx所以y^(-1)=(-2)·√(1-3x)/3·coos²√(1-3x)因为y’=1/[y^(-1)
y=lncosarctan(shx)求导因为dy=d[cosarctan(shx)]/cosarctan(shx)=-[sinarctan(shx)]*d[arctan(shx)]/cosarctan(shx)=-[tanarctan(sh
arctan方法1、(atctanx)'=1/(tany)'=1/sec^2y=1/(1+tan^2y)=1/(1+x^2)利用反函数求导法则方法2、lim(h-->0)(arctan(x+h)-arctanx)/h令arctan(x+h)
ln(x^2+y^2)=arctan(y/x)求导隐函数求导方程两边对x求导(2x+2yy')/(x^2+y^2)=[(xy'-y)/x^2]/[1+(y/x)^2]2(x+yy')/(x^2+y^2)=(xy'-y)/(x^2+y^2)2
a=arctan(3.2/x)-arctan(1.8/x)求导的过程RT,但一直做错,不好意思,它的答案是1.8/(x^2+1.8^2)-3.2/(x^2+3.2^2)我就是不知道怎么出来的那个,它求导数为0时,x的值楼上的错了.这是嵌套的
arctan(y/x)对y求导怎么求啊?再对x积分呢?arctan(y/x)对y求导是什么?答案说是x/(x^2+y^2),不是x^2/(x^2+y^2)么?怎么算的?给个步骤好吗?再对xdx/(x^2+y^2)求积分又是怎么求?详细点好吗
arctan(x)、arccot(x)、arcsin(x)、arccos(x)各自求导等于多少?都换成反函数,再用复合函数求导法。——————————————————————y=arcsinxsiny=xcosy*y'=1y'=1/cosy
对y=9arctan(x-根号下(1+x²))求导原题是y=9tan(-1)(x+√(1+x^2))y'=9*1/[1+(x+√1+x^2)^2]*[1+x/√(1+x^2)]=9/[2+2x^2+2x√(1+x^2)]*[√(1