cos(xy)=x隐函数的导数

导数cos(xy)=x的导数y=1/x*arccosx求导：y¹=1/x^2*[-x*1/√(1-x^2)-arccosx]导数cos(xy)的导数应该是-sin(xy).y吧

求隐函数的导数xy-cos(y)=0xy=cos(y)两边分别求导y'x+y=-sin(y)(y')y'x+sin(y)(y')=yy'=y/(siny+x)xy-cos(y)=0xy'+y+(siny)y'=0(x+siny)y'=-yy

cos(xy)=x求隐函数的导数dy/dxcos(xy)=x两边对x求导：-sin(xy)[y+xy']=1y+xy'=-1/sin(xy)xy'=-y-(1/sin(xy))y'=[-y-(1/sin(xy))]/xcos(xy)=x.关

cos(xy)=x－y所确定的隐函数y=y(x)的导数dy/dx快cos(xy)=x-y,隐函数,两边求导-sin(xy)*(xy)'=1-y'-sin(xy)*(y+xy')=1-y'-ysin(xy)-xcos(xy)*y'=1-y'y

由方程e^xy+y^3-cos(x-y)=0所确定的隐函数的导数对两边取对数：xy+3lny=lncos(x-y)两边同时对x求导：y+xy'+y'*3/y=-tan(x-y)*(1-y')整理得：y'=tan(x-y)+y/tan(x-y

隐函数x=ln(xy)的导数怎样求x=ln(xy)x=lnx+lny1=1/x+(1/y)*y'(-1/y)y'=1/x-1y'=-y/x+y1=(xy)'/(xy)y+xy'=xyy'=y-y/x两边对x求导得：1=（y+xy'）/xy所

e^x+xy=e^y隐函数的导数(e^x+xy)'=(e^y)'e^x+y+xy'=y'e^x,y'=(e^x+y)/(e^x-x)

求一函数的偏导数和全微分设f(x,y)=sin(xy)+cos(y/x)具有一阶偏导数,求函数f(x,y)的偏导数和全微分.有没有人知道怎么做,f'x=ycos(xy)-sin(y/x)(-y/x²)=ycos(xy)+(y/x&

求导数cos(xy)=x,用隐函数求导法设F(x,y)=x-cos(xy),则F'x=1+ysin(xy),F'y=xsin(xy)所以dy/dx=-F'x/F'y=-[(1+ysin(xy)]/[xsin(xy)]

求方程e^（x+y)-cos(xy)=0所确定的隐函数y=F(x)在x=0处导数x=0时,代入原方程得：e^y-cos0=0,得：y(0)=0对x求导：e^(x+y)*(1+y')+sin(xy)*(y+xy')=0因此y'=-[ysin(

求方程e^（x+y)-cos(xy)=0所确定的隐函数y=F(x)在x=0处导数e^（x+y)-cos(xy)=0两边同时对x进行求导：e^(x+y)*(1+y')+sin(xy)*(y+x*y')=0当x=0时,e^(y)*(1+y')+

求由方程ysinx-cos(xy)=0所确定的隐函数y=y(x)的导数dy/dxysinx=cos(xy)两边分别求导y'sinx+ycosx=-sin(xy)(y+xy')y'=-y(sin(xy)+cosx)/(sinx+xsin(xy

求隐函数所确定的函数的导数由隐函数方程xy^3-4x^2=xy+7所确定的函数的导数对方程两边求导可得y³+x(3y²y')-8x=y+xy'整理得,y'=(8x+y-y³)/(3xy²-x)(y^3

求函数的导数y=cos(4-3x)y'=-sin(4-3X)*(-3)=3sin(4-3X)

求函数y=cos^5(x/2)的导数设Z=X/2,则Z(x)'=1/2,设U=cos(X/2)=cosZ,U(x)'=U(z)'·Z(x)'=(-sinZ)·(1/2)=-(1/2)sin(X/2)Y=[COS(x/2)]^5=U^5,所以

函数y=cos(-x)的导数是什么?-(-sin(-x))=sin(-x),对cos(-x)求导,再对（-x)求导就行了

求函数的导数y=cos³4x全部展开收起

求函数z=xy+x/y的偏导数z=xy+x/y对x的偏导数=y+1/y对y的偏导数=x-x/y^2

求导：已知y=cos（xy）,求y的一阶导数（用隐函数求导）对等式两边求导,得y'=-sin(xy)*(y+xy')y'=-ysin(xy)/[xsin(xy)+1]

x+xy-x(y^3)=3的隐函数的导数dy/dx1+y+xy’-y^3-3xy^2y’=0(x-3xy^2)y’=y^3-y-1dy/dx=(y^3-y-1)/(x-3xy^2)口诀：对x求导时,把y看成常数；对y求导时,记住y是x的函数