limx→0（cos2x/cos5x)-热点作业-学帮网

limx→0ln(cos5x)/ln(cos2x)要过程用洛比达法则,limx→0ln(cos5x)/ln(cos2x)=limx→05sin5xcos2x/（2cos5xsin2x）=limx→05sin5x/（2sin2x）=limx→

limln（cos5x)/ln(cos2x)其中x趋向于0.求这个函数的极限~limx→05sin5x/（2sin2x）=limx→025x/4x=25/4.为什么这么直接?怎么一下子就到25x/4x了?这是高数里的知识.当x→0时,sin

求极值lim(x→0)(cos5x-cos3x)/x²lim(x→0)(cos5x-cos3x)/x²显然x趋于0的时候,分子cos5x-cos3x和分母x²都趋于0满足洛必达法则使用的条件,那么原极限=lim

求极限lim(x→0)(cos5x-cos3x)/x2lim(x→0)(cos5x-cos3x)/x^2=lim(x→0)(-2sin4x*sinx)/x^2=-2*lim(x→0)(sin4x*sinx)/x^2=-2*lim(x→0)[

求极限limx0时1-cos2x/xsinx等于多少参考一下~1-cos2x=2(sinx)^2利用等价无穷小式子=2x^2/x^2=2

limx趋于0,（cos2x)^(1/x^2)=设y=(cos2x)^(1/x^2)lny=(1/x²)lncos2xlny=(lncos2x)/x²lim[x-->0]lny=lim[x-->0](lncos2x)/x

求极限limx0时1-cos2x/sinx等于多少limx0时1-cos2x/sinx=limx0时[（2x）²/2]/x=0

limx趋于0,（cos2x)^(1/x^2)=求极限：x→0lim(cos2x)^(1/x²)x→0lim(cos2x)^(1/x²)=x→0lime^[(lncos2x)/x²]=x→0lime^[(-2s

cosx*cos2x*cos3x*cos4x*cos5x怎么化简?结果是多少?=cos2;2xcos2;x-1cos2;2xcos2;x-cos2;2xcos2;x=cos2;2xcos2;x-1=(1cos4x)/2(1cos2x)/2-

COSX+COS2X+COS3X+COS4X+COS5X+COS6X+...+COSNX=1/2|{SIN(N+1/2)X-SIN(2/X)}/SIN(2/X)|怎么证明利用e^(ix)=cosx+isinx；e^(ix)+e^(i2x)+

1)limx趋于0,1-cos2x/xsin2x,求极限值2)limx趋于兀,sin3x/x-兀,求极限值请各位学过高数的指点一下.要详细过程,谢谢!1)limx趋于0,1-cos2x/xsin2x=lim(x→0)[(2x)²/

求lim(x→0)(cos2x)^x^1/2以及limx(x→∞)(lnx)^[1/(x-1)]要过程第一个用对数求极限法lim(x→0)(cos2x)^(x^(1/2))设y=(cos2x)^(x^(1/2))lny=x^(1/2)*ln

函数极限问题limx趋向于01-cos2x/x^2lim(1-cos2x)/x^2(0/0型用罗比达法则）(x趋于0)=lim2sin2x/2x(x趋于0)用等价无穷小=2lim(1-cos2x)/x²=lim2sin²

求极限limx0时1-cos2x/sinx等于多少（求化简详细过程）lim(x→0)(1-cos2x)/sinx=lim(x→0)2sin²x/sinx=lim(x→0)2sinx=01-cos2x都是在分子上吧？1-cos2x=

limx趋近于0(cosx/cos2x)^(1/sinxsin2x)三角函数的极限求解答案是e^{3/4}.被求极限的式子记为F.因为limitcos(x)/cos(2x)=1>0,所以可以取对数:ln(F)=[ln(cos(x)cos(2

limx趋近于02cos2xsinx/2sin4xcosx为啥cos2x/cosx的极限等于一啊x→0时,直接代入就可以得出cos2x/cosx＝1lim(x→0)cos2x/cosx=lim(x→0)[2(cosx)^2-1]/cosx=

cos2x乘于cos3x怎样变形2分之一的(cos5x+cosx)高手请赐教哈cos2Xcos3X=二分之cos5X+cosX可以化成2cos2xcos3x=cos5x+cosx然后cos5x+cosx可以化成2cos（5x+x）/2*co

limx→0 tan2x/sinx

limx→0tan2x/sinxlimx→0tan2x/sinx=limx→0sin2x/(sinxcos2x)=limx→02sinxcosx/(sinx)=2使用等効代换=2x/x=2