t-sint1-cost

t/(1+cost)的不定积分t/(1+cost)=t/[2cos^2(t/2)]=(t/2)sec^2(t/2)原式=∫t/(1+cost)dt=∫td[tan(t/2)]=t*tan(t/2)-∫tan(t/2)dt=t*tan(t/2

itdoesn'tcostas它花费不多

为什么∫(2sint+cost)+2(2cost-sint)/2sint+costdt=(t+2ln|2sint+cost|)+C?因为∫[(2sint+cost)+2(2cost-sint)]/(2sint+cost)dt=∫(2sint

求解不定积分∫[t*e^(-cost)]dt它的不定积分不是初等函数,不能用具体式子表示!1

Theholidayshouldn'tcostverymuch.度假不该花太多钱!度假不会花很多钱

t趋于0时为什么lim(sint+cost-1)/t=lim(cost-sint)=1)你们没学过吗0/0型求极限,分子分母同时对t求导数,再把t=0带进导数里.

Thecar__muchmoney.Aisn'tcostBdidn'tcost选哪个怎么解释Bcost是动词,要用助动词be动词不可以直接跟动词连用

balanceT/Tpaymentbeforedelivery,EN-71costcollectby余款采用发货前TT电汇,EN71的快递费用由买家付款

(cost-1)/t的极限t趋于0答：0---0型可导,应用洛必达法则lim(t→0)(cost-1)/t=lim(t→0)-sint=0或者：lim(t→0)(cost-1)/t=lim(t→0)-2*[sin(t/2)]^2/t=lim

lim(sin2t+cost)的T分之一次方t-->o这道挺棘手的,先用洛必达法则好了lim[t→0](sin2t+cost)^(1/t)=e^lim[t→0]ln(sin2t+cost)^(1/t)=e^lim[t→0]ln(sin2t+

t趋向于0+,lim(1-cost)/t是多少?1-cost趋向于t²/2所以lim(1-cost)/t=limt/2=0

(sint+cost)/(cost-sint)怎么算的,等于tan(t+π/4)(sint+cost)/(cost-sint)=[(sint+cost)/√2]/[(cost-sint)/√2]=(sintcosπ/4+costsinπ/4

x=2t+costy=t+e^t求dy/dx把t消除=(1+e^t)/(2-sint)不通,看书.

Thehouseisworth---becauseitdosen'tcostmuch.A.beingboughtB.buying为啥选B?因为worth没有被动语态的形式.worthdoingsth：值得做某事；B...beworthdoi

为什么sint/(1-cost)=cot(t/2)sint=2sin(t/2)cos(t/2)1-cost=1-(1-2sin²(t/2))=2sin²(t/2)所以sint/(1-cost)=2sin(t/2)cos(

HowmuchdoestheT-shirtcost(同义句转换)What'sthepriceoftheT-shirt?HowmuchistheT-shirt?HowmuchtheT-shirt？

Somedon"tcostanythingatall,butothersareverydear出场费反反复复丰富

theyellowsweaterdoesn'tcost_____theredoneAasmanyasBasmuchasCasmoreasBmoney是不可数名词,所以只能用much形容,many是形容可数名词的,more是比较级BC-本题有

∫(t*cost)dt怎么求……∫tcostdt=∫td(sint)=tsint-∫sintdt,分部积分法=tsint+cost+c

thatshouldn't_long.A:costB:takeB.cost一般用于钱的方面.