(xy-x2)3-x3(y-x)

因式分解（xy-x2）3-x3(y-x)原题是否是这样的：（xy-x^2)^3-x^3(y-x)=x^3(y-x)^3-x^3(y-x)=x^3(y-x)〔(y-x)^2-1〕=x^3(y-x)(y-x+1)(y-x-1)（xy-x2）3-

因式分解（xy-x2）3-x3(y-x)(xy-x^2)^3-x^3(y-x)=x^3(y-x)^3-x^3(y-x)=x^3(y-x)[(y-x)^2-1]=x^3(y-x)(y-x+1)(y-x-1)（xy-x2）^3-x^3(y-x)

[x(x2次方Y2次方-XY)-Y(x2次方-X3次方Y)]除以3X2次方Y=[x*xy(xy-1)-y*x²(1-xy)]÷3x²y=[x²y(xy-1)+x²y(xy-1)]÷3x²y=

x3+6xy+y3=x3+y3+6xy=(x+y)(x2-xy+y2)+6xy为什么x3+y3+6xy可以化成(x+y)(x2-xy+y2)+6xy请为我解释一下恕我浅薄，就是x³+y³=(x+y)(x²-xy

推导公式:(x+y)(x2-xy+y2)=x3+y3(x+y)(x²-xy+y²)=x(x²-xy+y²)+y(x²-xy+y²)=x³-x²y+xy²

x3+y3怎样化成（x+y）（x2-xy+y2)x3+y3=x³+x²y-x²y-xy²+xy²+y³=x²(x+y)-xy(x+y)+y²(x+y)=(x+y

3x2+4xy-y2因式分解2x(x-y)4-x2(x-y)2+xy((y-x)2x3-13x-12x3+2x2+2x+12x3+x2-5x+2（答案的样子后面附图）第一个：原式=3x²+4xy+4/3y&sup2

已知:x+y=5,xy=3,x3+y3=(x+y)(x2-xy+y2),求x3分之1加上y3分之1x+y=5，xy=3，得x²+y²=(x+y)²-2xy=19x³+y³=(x+y)(x&#

X3+9+3X2+3X分解因式2X2+XY-Y2-4X+5Y-6分解因式X3+9+3X2+3X分解因式=（X3+3X2）+3X+9=x²（x+3）+3(x+3)=(x²+3)(x+3)2X2+XY-Y2-4X+5Y-6分

因式分解3x3-4x+1,-9x2+18xy-9y2+6x-6y-1,x4+x2-2,3x^3-4x+1=(3x^3-3)-(4x-4)=3(x-1)(x^2+x+1)-4(x-1)=(x-1)(3x^2+3x-1)-9x2+18xy-9y

(8xy-3x2)-5xy-3(xy-2x2+3)已知A=x3+x2-x+1,B=-x3-x2+x+1,当x=-2时,求A-2B的值.A=-6-4+2+1=-7,B=6+4-2+1=9A-2B=-7-2x9=-25(8xy-3*2)-5xy

x3-y3-x2+2xy-y2因式分解还有：(2)x2+2xy-3y2+3x+y+2(3)6x2-7x-4（实数范围内）1)x^3-y^3-x^2+2xy-y^2=x^3-y^3-(x^2-2xy+y^2)=(x-y)(x^2+xy+y^2

求导y=x3+x2-xy=x3+x2-x求出该函数的单调性和单调区间y'=3x^2+2x-1=(3x-1)(x+1)x1/3单调递增-1

(x-y)2(x2+xy+y2)2-(x3+y3)(-x3+y3),其中x=1,y=-1(x-y)²(x²+xy+y²)²-(x³+y³)(-x³+y³)=(x

已知：x+y=2分之1,xy=1.求x3次方y+2x2次方y的2次方+xy的3次方原式=xy(x²+2xy+y²)=xy(x+y)²=1×(1/2)²=1/4

化简求值:3(x2+xy)-2(x3-y3-3xy)+(-3xy-2y3),其中x=1,y=2=x6+3xy-x6+y6+6xy-6xy-6y=(6-6)x+(3+6)xy+y6-6y=9xy+y6-6y因：x=1y=2所：9xy+y6-6

A=x3-2y3+3x2y+xy2-3xy+4.B=y3-x3-4x2y-3xy-3xy2+3C=y3+x2y+2xy2+6xy试说明x、y的值对A+B+C无关A+B+C=（x3-2y3+3x2y+xy2-3xy+4）+（y3-x3-4x2

为什么（y3/z+z3/x+x3/y）(yz+zx+xy)>=(y2+x2+z2)2这个利用柯西不等式即可.将 （y3/z+z3/x+x3/y）(yz+zx+xy)改成平方和形式即可.

已知x+y+z=1,x2+y2+z2=2,x3+y3+z3=3,求xy(x+y)+yz(y+z)+zx(z+x)的值已知x+y+z=1,x²+y²+z²=2,x³+y³+z³=3,

求f(x)=x3-3xk,g(x)=(2kx-k)／(x22)y=x^3x-2X^2-3XY2Y^2an=1/n*(-1)^[(3n)/2]=-(-1)^(n/21/2)/n∩｛P丨PA=PC}所以(a-b)/sin(a-b)所以f（x3）