xcos^2x的不定积分-热点-学帮网

sin^2xcos^3x的不定积分,∫sin^2xcos^3xdx=∫sin^2x(1-sin^2x)dsinx=∫sin^2x-sin^4xdx=(1/3)sin^3x-(1/5)sin^5x+C实际非常简单∫sin^2x(1-sin^2

∫xcos(x+1)dx的不定积分=∫xdsin(x+1)=xsin(x+1)-∫sin(x+1)dx=xsin(x+1)+cos(x+1)+C分部积分

sin^2xcos^2x不定积分∫sin^2xcos^2xdx=1/4∫(sin2x)^2dx=1/8∫(1-cos4x)dx=1/8(x-1/4sin4x)+C=x/8-(sin4x)/32+C满意请采纳,

求不定积分∫xcos(x^2)dx∫xcos(x^2)dx=∫cos(x^2)(xdx)=∫cos(x^2)(d(x^2)/2)=(1/2)∫cos(x^2)d(x^2)=(1/2)sin(x^2)+C∫xcos(x^2)dx=1/2∫co

求x(cosx)^2的不定积分.不好意思，正确的是：xcos(x)^2的不定积分x(cosx)^2=1/2*x*(1+cos2x)=x/2+xcos2x/2然后分别积,分了吧,后面一项用分步积分

sin^2xcos^2x/(cos^3x+sin^3x)^2dx的不定积分积分结果：(3Cos[x]+Cos[3x]-8Sin[x]^3)/(18(Cos[x]+Sin[x])(-2+Sin[2x])),常数项自己加就可以了

1/(sin^4xcos^4x)的不定积分∫1/(sin^4xcos^4x)dx=∫16/sin^4(2x)dx=∫16csc^4(2x)dx=∫16[cot^(2x)+1]csc^2(2x)dx=-∫8[cot^2(2x)+1]dcot(

求不定积分(1/sin^2xcos^2x)dx原式=∫4dx/(2sinxcosx)²=4∫dx/sin²2x=2∫csc²2xd2x=-2cot2x+C原式=∫4/4sin^2xcos^2xdx=∫4/sin

求不定积分,∫sin^2xcos^2xdx利用半角公式如图降次计算.经济数学团队帮你解答,请及时采纳.

求不定积分：∫xcos(4x^2+5)dx∫xcos(4x^2+5)dxlet4x^2+5=tdt=d(4x^2+5)=4d(x^2)=4*2xdx=8xdxsodx=[dt/8x]∫xcos(4x^2+5)dx=∫xcostdt/8x=1

不定积分：∫xcos^2xdxcos^2x=(cos2x+1)/2∫xcos^2xdx=∫x(cos2x+1)dx/2+C=(∫xcos2xdx+∫xdx)/2+C=(∫xdsin2x+x^2)/4+C=(xsin2x-∫sin2xdx+x

不定积分：∫xcos^2xdx∫xcos^2xdx=∫x(1+cos2x/2)dx=1/2∫xdx+1/2∫xcos2xdx=x²/4+1/4∫xdsin2x=x²/4+1/4*xsin2x-1/4∫sin2xdx=x&

∫xcos(x-1)dx不定积分∫xcos(x-1)dx=∫cos(x-1)d(x^2/2)=cos(x-1)*x^2/2-∫xd(cos(x-1)+c=cos(x-1)*x^2/2+∫sin(x-1)d(x^2/2)+c=cos(x-1)

xcos派xdx求不定积分

求不定积分cos2x/sin^xcos^x微分转化过程为：(cos2x/sinxcosx)dx=(2cos2x/sin2x)dx=(1/sin2x)d(sin2x)令sin2x=t则：(cos2x/sinxcosx)dx=(1/t)dt=d

e^sinx（xcosx-（sinx/cos²x））的不定积分怎么算∫e^sinx(xcosx-sinx/cosx^2)dx=∫e^xsinx*xcosxdx-∫e^sinxsinxdx/(cosx)^2=∫xe^sinxdsin

SIN^4XCOS^4XD的不定积分不定积分SIN^4XCOS^4XDX=1/16*S（sin2x)^4dx=1/64*S(1-cos4x)^2dx=1/64*S(1-2cos4x+(cos4x)^2)dx=1/64*(Sdx-S2cos4

∫ln(tanx)/sinxcosxdx.不定积分的详细步骤过程和答案,拜托大神.intln(tanx)/(sinxcosx)dx=intln(tanx)*cosx/sinx*1/cos^2xdx=intln(tanx)*1/tanxd(t

计算不定积分∫xcos(x/2)dx求过程跟答案∫xcos(x/2)dx=2∫xcos(x/2)d(x/2)=2∫xdsin(x/2)=2xsin(x/2)-2∫sin(x/2)dx=2xsin(x/2)-4∫sin(x/2)d(x/2)=