因式分解:x^2+2xy+y^2-3x-3y+2(过程!)

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因式分解:x^2+2xy+y^2-3x-3y+2(过程!)

x^2+2xy+y^2-3x-3y+2
=(x+y)²-3(x+y)+2
=(x+y-1)(x+y-2)
十字相乘法
(x+y) -1
(x+y) -2

x^2+2xy+y^2-3x-3y+2
=(x+y)^2-3(x+y)+2
=(x+y-1)(x+y-2)

=(x+y)^2-3(x+y)+2
=(x+y-1)(x+y-2)

原式=(x+y)^2-3(x+y)+2
=(x+y-1)(x+y-2)

x^2+2xy+y^2-3x-3y+2
=(x+y)²-3(x+y)+2
=[(x+y)-2][(x+y)-1]
=(x+y-2)(x+y-1)