学帮网已知(4x+y-1)^2+|2y-2x+1|=0,求x,y的值
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已知(4x+y-1)^2+|2y-2x+1|=0,求x,y的值
(4x+y-1)^2+|2y-2x+1|=0
(4x+y-1)^2=0
|2y-2x+1|=0
4x+y-1=0
2y-2x+1=0
8x+2y=2
2y-2x=-1
8x-(-2x)=2-(-1)
10x=3
x=3/10
y=(2x-1)/2
y=(2*3/10-1)/2
y=-1/5
4x+y-1 = 0
2y-2x+1 = 0