f(x)=4sin^2(π/4+x)-2√3cos2x-1的导函数

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f(x)=4sin^2(π/4+x)-2√3cos2x-1的导函数

f'(x)=8sin(π/4+x)cos(π/4+x)+4√3sin2x

f(x)=2[1-cos(π/2+2x)]-2√3cos2x-1
=-2sin2x-2√3cos2x+1
=-4sin(2x+π/3)+1
所以f'(x)=-4cos(2x+π/3)*(2x+π/3)'+1
=-8cos(2x+π/3)+1已知函数f(x)=4sin2(4/π +x)-2√3cos2x-1,且满足条件p;“π/4≤x≤π/2” 若有...

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f(x)=2[1-cos(π/2+2x)]-2√3cos2x-1
=-2sin2x-2√3cos2x+1
=-4sin(2x+π/3)+1
所以f'(x)=-4cos(2x+π/3)*(2x+π/3)'+1
=-8cos(2x+π/3)+1

收起

4*3^(1/2)*sin(2*x) + 8*cos(π/4 + x)*sin(π/4 + x)