数学题化简再求值化简再求值那是x² ,不要看错了

数学题化简再求值
化简再求值
那是x²  ,不要看错了

原式=[1/(x+1)+(x-1)^2/(x+1)(x-1)]×[(x+1)/(x-1)]
=[1/(x+1)+(x-1)/(x+1)]×[(x+1)/(x-1)]
=x/(x+1)×[(x+1)/(x-1)]
=x/(x-1)

[1/(x+1)+（x²-2x+1）/（x²-1）】÷（x-1）/（x+1）
=(x-1+x²-2x+1）/[(x-1)(x+1)]*(x+1)/(x-1)
=x(x-1）/[(x-1)(x+1)]*(x+1)/(x-1)
=x/(x-1)

由于没有给出X的具体值，故无法求代数式值

希望可以帮到你。

解:原式=[1/（x 1） （x-1)/（x 1）] (x-1)/(x 1)
=(1 x-1 x-1)/(x 1)
=(2x-1)/(x 1)