初二的异分母相加 1/(x-1)(x-2)+1/(x-2)(x-3)

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初二的异分母相加 1/(x-1)(x-2)+1/(x-2)(x-3)

通分,分母变成(x-1)*(x-2)*(x-3) 分子变成(x-3)+(x-1)=2*(x-2) 化简得2/(x-1)(x-3) 敬请采纳