已知a

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已知a

√(a^2-2a+1)/(a^2-a)
=|a-1|/[a(a-1)]
=(1-a)/[a(a-1)]
=-1/a

没看明白题意

a<1
a-1<0
|a-1|=-(a-1)
原式=√(a-1)²/[a(a-1)]
=|a-1|[a(a-1)]
=-(a-1)/[a(a-1)]
=-1/a