y=3x–2/x+1=3(x+1)–5/x+1=3+(-5/x+1) 这是怎么算的?y=3x–2/x+1=3(x+1)–5/x+1=3+(-5/x+1)这是怎么算的?
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y=3x–2/x+1=3(x+1)–5/x+1=3+(-5/x+1) 这是怎么算的?
y=3x–2/x+1=3(x+1)–5/x+1=3+(-5/x+1)
这是怎么算的?
y=3x–2/x+1
=(3x–2)/(x+1)
=(3x+3-3–2)/(x+1)
=[3(x+1)-5]/(x+1)
=3(x+1)/(x+1) - 5/(x+1)
=3 - 5/(x+1)
=3+[-5/(x+1)]
ok
明显是错误的。3x-2/x+1=3(x+1/x)-5/x+1
你题目上有问题吧:
y=(3x–2)/(x+1)=(3x+3-5)/(x+1)=[3(x+1)–5]/(x+1)=3(x+1)/(x+1)-5/(x+1)=3-5/(x+1)
有问题,少了括号吧。
y=(3x–2)/(x+1)
=(3x+3–5)/(x+1)
=[3(x+1)–5]/(x+1)
=[3(x+1)]/(x+1)+(-5)/(x+1)
=3+[-5/(x+1)]
应该能看懂了吧?
这是个分式
分子可以化为:3x–2 = 3(x+1)–5
分母为: x+1
一约分即为: 3 +(-5/x+1)
首先将分子中的3x写成3(x+1),那么后面就要减去5; 然后3(x+1)与x+1相除,结果就是3;后面就剩下了-5/(x+1)
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