函数f(x)是奇函数,g(x)是偶函数且f(x)+g(x)=1/(x+1)(x≠±1),则f(-3)=

函数f(x)是奇函数,g(x)是偶函数且f(x)+g(x)=1/(x+1)(x≠±1),则f(-3)=

f(3)＋g(3)＝1/4
f(-3)＋g(-3)＝-1/2,即-f(3)＋g(3)＝-1/2
两式相减得：f(3)＝3/8

h(x)=f(x)+g(x)=1/(x+1
由奇偶性
h(-x)=-f(x)+g(x0=1/(-x+1)
相减
2f(x)=1/(x+1)-1/(-x+1)
2f(-3)=-1/2-1/4=-3/4
f(-3)=-3/8