点A(X0,Y0)在双曲线X^2/4-Y^2/32=1的右支上,若点A带右焦点的距离等于2X0,则X0为

点A(X0,Y0)在双曲线X^2/4-Y^2/32=1的右支上,若点A带右焦点的距离等于2X0,则X0为

x^2/4-y^2/32=1
a^2=4,b^2=32,c^2=4+32=36
e=c/a=6/2=3
AF2=exo-a=3xo-2
又AF2=2Xo
故3xo-2=2xo
xo=2