把关于X的方程x²-x+1/x-1=a=1/a-1变形为方程x+1／x=c+1／c的形式是?方程的解是?已知答案是（x-1)+1/x-1=a-1+1/a-1，解是x1=a,x2=a/a-1 Q啊题目打错了是x²-x+1/x-1=a+1/a-1变形

把关于X的方程x²-x+1/x-1=a=1/a-1变形为方程x+1／x=c+1／c的形式是?方程的解是?
已知答案是（x-1)+1/x-1=a-1+1/a-1，解是x1=a,x2=a/a-1 Q啊题目打错了是x²-x+1/x-1=a+1/a-1变形

(x²-x)/(x-1)+1/(x-1)=a+1/(a-1)
x+1/(x-1)=a+1/(a-1)
两边减去1
(x-1)+1/(x-1)=(a-1)+1/(a-1)
这样吧x-1和a-1看做整体即可