约分:x²+x- 2/x²- x- 6

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约分:x²+x- 2/x²- x- 6

x²+x- 2/x²- x- 6
=(x+2)(x-1)/[(x-3)(x+2)]
=(x-1)/(x-3)

x²+x- 2/x²- x- 6
=(x-1)(x+2)/[(x-3)(x+2)]
=(x-1)/(x-3)

(x²+x-2)/(x²-x-6)
=(x+2)(x-1)/[(x-3)(x+2)]
=(x-1)/(x-3)