计算:[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y

来源：学生作业学帮网编辑：学帮网时间：2024/06/01 02:31:13

[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y
=(x^3y^2-x^2y-x^2y+x^3y^2)/3x^2y
=(2x^3y^2-2x^2y)/3x^2y
=2/3xy-2/3