(-2x^2)^3*(y^2+x^2+x^2y^2)的结果中,次数为10的项的系数是多少?

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(-2x^2)^3*(y^2+x^2+x^2y^2)的结果中,次数为10的项的系数是多少?

因为(-2x^2)^3*(y^2+x^2+x^2y^2)
=-8x^6*(y^2+x^2+x^2y^2)
=-8x^6y^2-8x^8-8x^8y^2,
而结果中次数为10的项是-8x^8y^2,
所以它的系数是-8.

次数为10的项的系数是(-2)^3=-8

10的项是：（-2)^3x^8y^2,它的系数是(-2)^3=-8

10

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