证明:[tan(x+y)-tanx]/1+tanxtan(x+y)=sin2x/2cosy^2

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证明:[tan(x+y)-tanx]/1+tanxtan(x+y)=sin2x/2cosy^2

左边=tan(x+y-x)=tany
右边=2sinycosy/2cos^2y
=siny/cosy
=tany
左边=右边
[tan(x+y)-tanx]/1+tanxtan(x+y)=sin2y/2cosy^2

啥东东啊?