函数y=cos（π/3-2x）+sin2x的最小正周期是

函数y=cos（π/3-2x）+sin2x的最小正周期是

y=cos（π/3-2x）+sin2x
=cosπ/3*cos(2x) + sinπ/3* sin(2x) +sin2x
=1/2 cos2x + [根号(3)/2 +1]sin2x
= Asin(2x + Φ)
T=π

T=π

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