(x+y分之y)-(y²-x²分之xy)
来源:学生作业学帮网 编辑:学帮网 时间:2024/05/14 20:22:06
(x+y分之y)-(y²-x²分之xy)
=y/(x+y)+xy/(x+y)(x-y)
=[y(x-y)+xy]/(x+y)(x-y)
=(2xy-y²)/(x²-y²)
原式=y(y-x)/(y+x)(y-x)-xy(y+x)(y-x)
=(y²-xy-xy)(y+x)(y-x)
=(y²-2xy)(y+x)(y-x)
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来源:学生作业学帮网 编辑:学帮网 时间:2024/05/14 20:22:06
(x+y分之y)-(y²-x²分之xy)
=y/(x+y)+xy/(x+y)(x-y)
=[y(x-y)+xy]/(x+y)(x-y)
=(2xy-y²)/(x²-y²)
原式=y(y-x)/(y+x)(y-x)-xy(y+x)(y-x)
=(y²-xy-xy)(y+x)(y-x)
=(y²-2xy)(y+x)(y-x)