已知函数f(x)=ax²+c且f'x(1)=0,求a的值

已知函数f(x)=ax²+c且f'x(1)=0,求a的值

1.当a=0时,满足f(x)=c,f'(1)=0.
2.当a不等于0时,f'(x)=2ax,
f'(1)=0,2a=0,
a=0
综上,a=0

f'(x) = 2ax
f'(1)= 2a*1 = 2a = 0
a = 0