函数f(x)=sin²x+sinxcosx的最小正周期为

函数f(x)=sin²x+sinxcosx的最小正周期为

f(x)=sin²x+sinxcosx
=1/2-1/2cos2x+1/2sin2x
所以周期2π/2=π

f(x)=sin²x+sinxcosx
=(1-cos2x)/2+(1/2)sin2x
=(√2/2)sin(2x-π/4)+1/2
所以函数f(x)=sin²x+sinxcosx的最小正周期为T=2π/2=π