5(x²-x)=3(x²+x)

5(x²-x)=3(x²+x)

5(x²-x)=3(x²+x)
5x²-5x=3x²+3x
2x²-8x=0
2x(x-4)=0
x=0,x=4

解由5(x²-x)=3(x²+x)
得5x²-5x=3x²+3x
即2x²-8x=0
即x²-4x=0
即x（x-4）=0
即x=0或x=4.