求证:sina-cosa+1/sina+cosa-1=tan(a/2+π/4)(sina-cosa+1)/(sina+cosa-1)=tan(a/2+π/4)
来源:学生作业学帮网 编辑:学帮网 时间:2024/05/17 02:12:23
求证:sina-cosa+1/sina+cosa-1=tan(a/2+π/4)
(sina-cosa+1)/(sina+cosa-1)=tan(a/2+π/4)
因为
(sina-cosa+1)/(sina+cosa-1)-tan(a/2+π/4)
=(sina-cosa+1)/(sina+cosa-1)-[1-cos(a+π/2)]/sin(a+π/2)]
=(sina-cosa+1)/(sina+cosa-1)-(1+sina) / cosa
=[cosa(sina-cosa+1)-(1+sina)(sina+cosa-1)] / [ cosa(sina+cosa-1)]
=[cosasina-cos²a+cosa-(sina+cosa-1+sin²a+cosasina-sina)] / [ cosa(sina+cosa-1)]
=[-cos²a+1-sin²a] / [ cosa(sina+cosa-1)]
=0
左边-右边=0
所以,
(sina-cosa+1)/(sina+cosa-1)=tan(a/2+π/4)成立
求证:1+sina+cosa/1+sina-cosa+1-cosa+sina/1+cosa+sina=2/sina
求证cosa/1+sina-sina/1+cosa=2(cosa-sina)/1+sina+cosa
求证:1+sina+cosa+2sina cosa/1+sina+cosa=sina+cosa
求证道数学题.(cosa-sina)/(1+sina+cosa)=cos/(1+sina)-sina/(1+cosa)
求证,2(cosA-sinA)/(1+sinA+cosA)=cosA/(1+sinA)-sinA/(1+sinA)把sinA/(1+sinA)改为sinA/(1+cosA)
求证,2(cosA-sinA)/(1+sinA+cosA)=cosA/(1+sinA)-sinA/(1+sinA)把sinA/(1+sinA)改为sinA/(1+cosA),详尽点.
求证1+sina-cosa/1+sina+cosa=tana/2
求证[sina(1+sina)+cos(1+cosa)][sina(1-sina)+cos(1-cosa)]=sin2a
求证:(1+sina+cosa+2sinacosa)/(1+sina+cosa)=sina+cosa
求证:1+sinA+cosA+2sinAcosA/1+sinA+cosA=sinA+cosA
求证:1+sina+cosa分之1+sina+cosa+2sinacosa=sina+cosa
求证(1+sina+cosa+2sinacosa)/(1+sina+cosa)=sina+cosa
求证(1-cos²a/sina-cosa)-(sina+cosa/tan²a-1)=sina+cosa
求证:2sina+sin2a=2(sina)^3/(1-cosa)(sina)^3/(1-cosa)=sina*(1+cosa) 看不懂
cota+(sina/(1+cosa))=1/sina 求证
求证(sina/2-cosa/2)^2=1-sina
求证sina(1+sina)+cosa(1+1/tana)=1/sina + 1/cosa
求证:sina(1+cos2a)=sin2a*cosa.