sin2α-cos2α+1/1+tanα怎样化简成2sinαcosα?

来源：学生作业学帮网编辑：学帮网时间：2024/05/30 18:18:33

=(2sinacosa+2sin^2a)/(1+sina/cosa)
=2sina*(sina+cosa)/[(sina+cosa)/cosa]
=2sina/(1/cosa)
=2sinacosa