有两个反比例函数y1=k1/x和y2=k2/x,当x=2时,y1+y2=1,y1-y2=3,求k1,k2的值

有两个反比例函数y1=k1/x和y2=k2/x,当x=2时,y1+y2=1,y1-y2=3,求k1,k2的值

将x=2代入y1+y2=1
k1/2+k2/2=1
k1+k2=2.(1)
x=2时,y1-y2=3
k1/2-k2/2=3
k1-k2=6.(2)
(1)+(2):2k1=8,k1=4
(1)-(2):2k2=-4,k2=-2
k1=4,k2=-2