x²-y²-3x-3y

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x²-y²-3x-3y

=(x+y)(x-y)-3(x+y)
=(x+y)(x-y-3)
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x²-y²-3x-3y=(x+y)(x-y)-3(x+y)=(x+y)(x-y-3)

x²-y²-3x-3y
=(x+y)(x-y)-3(x+y)
=(x+y)(x-y-3)