(1)3xy³/x²y=( )/x (2)4/x-1=( )/(x-1)(x+1)

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(1)3xy³/x²y=( )/x (2)4/x-1=( )/(x-1)(x+1)

(1)3xy³/x²y=(3y² )/x (2)4/x-1=( 4x+4)/(x-1)(x+1)

(1)3xy³/x²y=(3y² )/x
(2)4/x-1=( 4x+4)/(x-1)(x+1)

(1)3y²
(2)4/x+4