若3x^2+4y-10=0,则15x^3+3x^2y+20xy+4y^2+3x^2-50x-6y=

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若3x^2+4y-10=0,则15x^3+3x^2y+20xy+4y^2+3x^2-50x-6y=

3x^2+4y-10=0,
3x^2+4y=10
15x^3+3x^2y+20xy+4y^2+3x^2-50x-6y
=(15x^3+20xy)+(3x^2y+4y^2)+(3x^2+4y)-50x-10y
=5x(3x^2+4y)+y(3x^2+4y)+(3x^2+4y)-50x-10y
=50x+10y+10-50x-10y
=10