已知|x-1|+(y+3)²+√(x+y+z)=0,求4x+3y+2z的值

已知|x-1|+(y+3)²+√(x+y+z)=0,求4x+3y+2z的值

已知|x-1|+(y+3)²+√(x+y+z)=0
则x-1=y+3=x+y+z=0(每个都≥0）
x=1
y=-3
z=2
4x+3y+2z
=4-9+4
=-1