①2001÷2001又2001/2002+1/2003 ②633×210-(5697×28.3+717×569.7)×11/90我不要求两道都会的,有一道会写就行,当然两道最好,请写下计算过程,

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①2001÷2001又2001/2002+1/2003 ②633×210-(5697×28.3+717×569.7)×11/90
我不要求两道都会的,有一道会写就行,当然两道最好,请写下计算过程,

2001÷2001又2001/2001
=2001/[(2001×2002+2001)/2002]
=2001/[(2002×2002)/2002]
=2001/2002
633×210-(5697×28.3+717×569.7)×11/90
=633×210-(5697×28.3+71.7×5697)×11/90
=633×210-(28.3+71.7)×5697×11/90
=633×210-100×5697×11/90
=633×210-110×56970/90
=633×210-110×633
=633×100
=63300