化简求值 (2x³-xyz)-2(x³-y³+xyz)+(xyz-3y³) x=1 y=-2 z=-3

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化简求值 (2x³-xyz)-2(x³-y³+xyz)+(xyz-3y³) x=1 y=-2 z=-3

(2x³-xyz)-2(x³-y³+xyz)+(xyz-3y³)
= 2x³-xyz-2x³+2y³-2xyz+xyz-3y³
=-y³-2xyz
=-y(y²+2xz)
=2×(4-6)
=-4

当x=1 y=-2 z=-3 时
(2x³-xyz)-2(x³-y³+xyz)+(xyz-3y³)
=2x³-xyz-2x³+2y³-2xyz +xyz-3y³=-2xyz-y³=-2×1×(-2)×(-3)-(-3)³
=-12+27=15