函数f(x)=sin(2x-π/4)-2根号2(sinx)^2的最小正周期是

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函数f(x)=sin(2x-π/4)-2根号2(sinx)^2的最小正周期是

f(x)=sin(2x-π/4)-2√2sin²x
＝sin2xcosπ/4-cos2xsinπ/4-√2（1－cos2x）
=√2/2 sin2x- √2/2 cos2x +√2cos2x-√2
=√2/2 sin2x+√2/2 cos2x-√2
=sin(2x+π/4)-√2
∴最小正周期是2π/2=π

函数f(x)=2sin(x+π/4)sin(x-π/4)+sin2x的值域 已知函数f(x)=(1+1 anx)sin^2x+m sin(x+π/4)sin(x-π/4) 设函数 f(x)=sin(2x+y),(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 已知函数F(X)=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 函数f(x)=sin(2x+a) -π 设函数f(x)=sin(2x+ φ)(-π 函数f(x)=sin(2x+&）(-π 函数f(x)=sin(2x+t) (-π 函数f(x)=sin(2x+a）(-π