解(x-2)(x+1)(x+4)(x+7)=19

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解(x-2)(x+1)(x+4)(x+7)=19

[(x-2)(x+7)][(x+1)(x+4)]=19
(x^2+5x-14)*(x^2+5x+4)=19
设x^2+5x=a,则
(a-14)(a+4)=19
化简得 a^2-10a-75=0
∴(a-15)(a+5)=0
a=15 或者 a=-5
①当a=15时,则
x^2+5x=15
解得x=(-5±√85)/2
②当y=-5时,则
x^2+5x+5=0
解得x=(-5±√5)/2

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