根号(1-2sin(π+2)cos(π+2))等于?

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根号(1-2sin(π+2)cos(π+2))等于?

根号(1-2sin(π+2)cos(π+2))
=根号[(sin2)^2+(cos2)^2-2sin2cos2
=根号[(sin2+cos2)^2]
=|sin2+cos2|
=sin2+cos2

sin2-cos2