[(x-y)²+(x+y)²](x²-y²)计算

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[(x-y)²+(x+y)²](x²-y²)计算

原式=(x²-2xy+y²+x²+2xy+y²)(x²-y²)
=2(x²+y²)(x²-y²)
=2(x⁴-y⁴)
=2x⁴-2y⁴

原式
（x²-2xy+y²+x²+2xy+y²)(x2-y²)
=(2x²+2y²)(x²-y²)
=2(x²+y²)(x²-y²)
=2(x4-y4)


原式=(2x²+2y²)(x²-y²)
=2(x^4-y^4)