∫x^2/(1+^2)dx,∫sin^2xdx计算不定积分

来源：学生作业学帮网编辑：学帮网时间：2024/05/05 00:15:37

∫ x^2/(1+x^2)dx
= ∫ (1 - 1/(1+x^2))dx
= x - arctan(x) + C
∫ sin^2xdx
= 1/2 ∫ (1 - cos(2x))dx
= 1/2 (x - 1/2 sin(2x)) + C

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