b/lnb>a/lna;求证a^b>b^a

b/lnb>a/lna;求证a^b>b^a

你上初中还是高中?
解法是这样的：
b/ln b>a/ln a => b*(In a)>a*(ln b) => ln a^b>In b^a => a^b>b^a
OK了,但是我建议你,遇到这样的题还是自己先做做.