一道八年级上的二次根式计算题-2²×√8+3√2(3-2√2)-1/(1+√2)

来源:学生作业学帮网 编辑:学帮网 时间:2024/06/04 10:11:21

一道八年级上的二次根式计算题
-2²×√8+3√2(3-2√2)-1/(1+√2)

-2²×√8+3√2(3-2√2)-1/(1+√2)
=-4*2√2+9√2-12-(√2-1)
=-8√2+9√2-12-√2+1
=-11

-2²×√8+3√2(3-2√2)-1/(1+√2)
=-4*2√2+9√2-12-(√2-1)
=-8√2+9√2-12-√2+1
=-11

=-4×2√2+9√2-12-(√2-1)
=-8√2+9√2-12-√2+1
=-11