分解因式x²-y²-3x-3y

来源：学生作业学帮网编辑：学帮网时间：2024/06/02 11:04:19

分解因式x²-y²-3x-3y

x²-y²-3x-3y=x²-y²-3(x+y)
=(x+y)(x-y)-3(x+y)
=(x+y)[(x-y)-3]
=(x+y)(x-y-3)

原式=(x+y)(x-y)-3(x+y)
=(x+y)(x-y-3)

x²-y²-3x-3y
=(x²-y²)-(3x+3y)
=(x+y)(x-y)-3(x+y)
=(x+y)[(x-y)-3]
=(x+y)(x-y-3)