|x+2|+(y-1/4)²=0,求2(x²y+xy)-3(x²y-xy)-4x²y的值

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|x+2|+(y-1/4)²=0,求2(x²y+xy)-3(x²y-xy)-4x²y的值

∵|x+2|+(y-1/4)²=0
∴x+2=0
x=-2
y-1/4=0
y=1/4
xy=-1/2
x²y=1
代入上式
2(1-1/2)-3(1+1/2)-4
=1-9/2-4
=-15/2