初二数学下册已知ABC=1求1/（AB+A+1）+1/(BC+B+1)+1/(AC+C+1)的值

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初二数学下册已知ABC=1求1/（AB+A+1）+1/(BC+B+1)+1/(AC+C+1)的值

1/（AB+A+1）+1/(BC+B+1)+1/(AC+C+1)
=1/(1/C+A+1)+1/(BC+1/AC+1)+1/(AC+C+1)
=C/(1+AC+C)+AC/(C+1+AC)+1/(AC+C+1)
=(C+AC+1)/(1+AC+C)
=1

1

= 1