f(x)=1+2sin(2x+π/6),若f(x)=1-根号3,且x∈[-π/3,π/3]求x?

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f(x)=1+2sin(2x+π/6),若f(x)=1-根号3,且x∈[-π/3,π/3]求x?

1+2sin(2x+π/6)=1-√3
sin(2x+π/6)=-√3/2
-π/3