(lg2)^3+(lg5)^3+lg5*lg8怎么算谢谢!
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(lg2)^3+(lg5)^3+lg5*lg8怎么算谢谢!
令a=lg2,b=lg5
则a+b=lg2+lg5=1
lg8=lg2^3=3lg2=3a
所以原式=a^3+b^2+3ab
=(a+b)(a^2-ab+b^2)+3ab
=1*(a^2-ab+b^2)+3ab
=a^2+2ab+b^2
=(a+b)^2
=1
lg2(lg5-lg2)-lg5(lg5+3lg2)等于
(lg2)^3+(lg5)^3+3*lg2*lg5
(lg2)³+(lg5)³+3lg2×lg5
3+lg5+(lg2)^2
3lg2-lg5=
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(lg2)^3+(lg5)^3+3lg2*lg5的值为?
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求解3lg5+3lg2*lg5+3lg2^2~
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(lg2)³+(lg5)³+3lg2×lg5=?
(lg2)³+3lg2*lg5+(lg5)³等于多少
(lg²2-lg2*lg5+lg²)+3lg2*lg5