(a+b)²+|b-1∕3|=0 求(5a²b-2ab²-3ab)-(2ab+5a²b-2ab²)

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(a+b)²+|b-1∕3|=0 求(5a²b-2ab²-3ab)-(2ab+5a²b-2ab²)

a+b=0
b-1/3=0
b=1/3
a=-1/3
(5a²b-2ab²-3ab)-(2ab+5a²b-2ab²)
=5a²b-2ab²-3ab-2ab-5a²b+2ab²
=-5ab
=-5(-1/3)*(1/3)
=5/9

5/9