因式分解(a-1)x²-(a²+1)x+a²+a,
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因式分解(a-1)x²-(a²+1)x+a²+a,
(a-1)x²-(a²+1)x+a²+a
=(a-1)x²-(a²+1)x+a(a+1)
=(x-a)[(a-1)x-(a+1)]
(a-1)x²-(a²+1)x+a²+a
=(a-1)x²+(a²-1)x+a(a+1)
=(a-1)x²+(a+1)(a-1)x-a(a-1)
提公因式(a-1)
=(a-1)(x²+a+1-a)
=(a-1)(x²+a)